Sonneborn–Berger score

How the Sonneborn–Berger score is calculated in round-robin tournaments: the points of the opponents you beat plus half the points of those you drew with. A worked example

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Contents
  1. How to calculate it
  2. Example
  3. When it is used

The Sonneborn–Berger score is a tiebreak criterion for round-robin tournaments, where everyone plays everyone. It shows against whom a player scored their points: wins over strong opponents count for more than wins over weak ones.

How to calculate it

A player's Sonneborn–Berger score equals:

  • the sum of the points of all opponents they beat,
  • plus half the points of the opponents they drew with.

Losses add nothing.

Example

A four-player tournament, each player has played three games:

ABCDPoints
A—½1½2
B½—½12
C0½—11½
D½00—½

A and B have 2 points each. Let us calculate their scores:

  • A beat C (1½ points) and drew with B (half of 2 = 1) and D (half of ½ = ¼). Total: 1½ + 1 + ¼ = 2¾.
  • B beat D (½ point) and drew with A (half of 2 = 1) and C (half of 1½ = ¾). Total: ½ + 1 + ¾ = 2¼.

First place goes to A: their win was against a stronger opponent.

When it is used

The Sonneborn–Berger score is used in round-robin tournaments, usually after the direct encounter. The order of tiebreak criteria is set in advance in the tournament regulations. For Swiss-system tournaments the Buchholz score is more suitable.

Other ways of deciding places are covered in the article “Tiebreak”.